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10314252067 = 71473464581
BaseRepresentation
bin10011001101100011…
…01111111100100011
3222121211002021220211
421212301233330203
5132110422031232
64423250114551
7513411460510
oct114661577443
928554067824
1010314252067
114413143269
121bba27ba57
13c84b38342
146dbba6307
15405784a47
hex266c6ff23

10314252067 has 4 divisors (see below), whose sum is σ = 11787716656. Its totient is φ = 8840787480.

The previous prime is 10314251999. The next prime is 10314252073. The reversal of 10314252067 is 76025241301.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 76025241301 = 81193742591.

It is not a de Polignac number, because 10314252067 - 219 = 10313727779 is a prime.

It is a super-2 number, since 2×103142520672 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10314253067) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 736732284 + ... + 736732297.

It is an arithmetic number, because the mean of its divisors is an integer number (2946929164).

Almost surely, 210314252067 is an apocalyptic number.

10314252067 is a deficient number, since it is larger than the sum of its proper divisors (1473464589).

10314252067 is an equidigital number, since it uses as much as digits as its factorization.

10314252067 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1473464588.

The product of its (nonzero) digits is 10080, while the sum is 31.

Adding to 10314252067 its reverse (76025241301), we get a palindrome (86339493368).

The spelling of 10314252067 in words is "ten billion, three hundred fourteen million, two hundred fifty-two thousand, sixty-seven".

Divisors: 1 7 1473464581 10314252067