Base | Representation |
---|---|
bin | 110000000010001000… |
… | …0000110010100000100 |
3 | 100212020201221120022102 |
4 | 1200010100012110010 |
5 | 3142223014403012 |
6 | 115215310051232 |
7 | 10311111105236 |
oct | 1400420062404 |
9 | 325221846272 |
10 | 103150544132 |
11 | 3a82287a589 |
12 | 17ba8aa9b18 |
13 | 995b45373c |
14 | 4dc7654256 |
15 | 2a3ab192c2 |
hex | 1804406504 |
103150544132 has 6 divisors (see below), whose sum is σ = 180513452238. Its totient is φ = 51575272064.
The previous prime is 103150544111. The next prime is 103150544153. The reversal of 103150544132 is 231445051301.
It is an interprime number because it is at equal distance from previous prime (103150544111) and next prime (103150544153).
It can be written as a sum of positive squares in only one way, i.e., 91292205316 + 11858338816 = 302146^2 + 108896^2 .
It is a junction number, because it is equal to n+sod(n) for n = 103150544095 and 103150544104.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12893818013 + ... + 12893818020.
It is an arithmetic number, because the mean of its divisors is an integer number (30085575373).
Almost surely, 2103150544132 is an apocalyptic number.
It is an amenable number.
103150544132 is a deficient number, since it is larger than the sum of its proper divisors (77362908106).
103150544132 is a wasteful number, since it uses less digits than its factorization.
103150544132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25787636037 (or 25787636035 counting only the distinct ones).
The product of its (nonzero) digits is 7200, while the sum is 29.
Adding to 103150544132 its reverse (231445051301), we get a palindrome (334595595433).
The spelling of 103150544132 in words is "one hundred three billion, one hundred fifty million, five hundred forty-four thousand, one hundred thirty-two".
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