Base | Representation |
---|---|
bin | 11110000010010010011… |
… | …01100100010100000001 |
3 | 10122122211021112112112212 |
4 | 33001021031210110001 |
5 | 113402034213210132 |
6 | 2110034215431505 |
7 | 134363300016254 |
oct | 17011115442401 |
9 | 3578737475485 |
10 | 1032020444417 |
11 | 36874a6aa7a6 |
12 | 148019685595 |
13 | 7641c115781 |
14 | 37d42d4d09b |
15 | 1bca29405b2 |
hex | f049364501 |
1032020444417 has 2 divisors, whose sum is σ = 1032020444418. Its totient is φ = 1032020444416.
The previous prime is 1032020444359. The next prime is 1032020444447. The reversal of 1032020444417 is 7144440202301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 741374382961 + 290646061456 = 861031^2 + 539116^2 .
It is an emirp because it is prime and its reverse (7144440202301) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1032020444417 is a prime.
It is not a weakly prime, because it can be changed into another prime (1032020444447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 516010222208 + 516010222209.
It is an arithmetic number, because the mean of its divisors is an integer number (516010222209).
Almost surely, 21032020444417 is an apocalyptic number.
It is an amenable number.
1032020444417 is a deficient number, since it is larger than the sum of its proper divisors (1).
1032020444417 is an equidigital number, since it uses as much as digits as its factorization.
1032020444417 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21504, while the sum is 32.
Adding to 1032020444417 its reverse (7144440202301), we get a palindrome (8176460646718).
The spelling of 1032020444417 in words is "one trillion, thirty-two billion, twenty million, four hundred forty-four thousand, four hundred seventeen".
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