Base | Representation |
---|---|
bin | 10111011101110011011010… |
… | …000110000110100101011011 |
3 | 111112102010022210120121201021 |
4 | 113131303122012012211123 |
5 | 102011340004101034321 |
6 | 1003254510452103311 |
7 | 30511115564244142 |
oct | 2735633206064533 |
9 | 445363283517637 |
10 | 103203133221211 |
11 | 2a97a226226571 |
12 | b6a9560604b37 |
13 | 457802415225a |
14 | 1b6b0b5d90759 |
15 | bde83c594941 |
hex | 5ddcda18695b |
103203133221211 has 2 divisors, whose sum is σ = 103203133221212. Its totient is φ = 103203133221210.
The previous prime is 103203133221163. The next prime is 103203133221239. The reversal of 103203133221211 is 112122331302301.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 103203133221211 - 217 = 103203133090139 is a prime.
It is not a weakly prime, because it can be changed into another prime (103203137221211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51601566610605 + 51601566610606.
It is an arithmetic number, because the mean of its divisors is an integer number (51601566610606).
Almost surely, 2103203133221211 is an apocalyptic number.
103203133221211 is a deficient number, since it is larger than the sum of its proper divisors (1).
103203133221211 is an equidigital number, since it uses as much as digits as its factorization.
103203133221211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 103203133221211 its reverse (112122331302301), we get a palindrome (215325464523512).
The spelling of 103203133221211 in words is "one hundred three trillion, two hundred three billion, one hundred thirty-three million, two hundred twenty-one thousand, two hundred eleven".
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