Base | Representation |
---|---|
bin | 10111011110000101010001… |
… | …001111110101010111100001 |
3 | 111112110221211102002010121001 |
4 | 113132011101033311113201 |
5 | 102012143243401130032 |
6 | 1003311401530432001 |
7 | 30512365056262153 |
oct | 2736052117652741 |
9 | 445427742063531 |
10 | 103222312130017 |
11 | 2a987378219623 |
12 | b6b1213592601 |
13 | 4579a8c6a0cc2 |
14 | 1b6bdb51baad3 |
15 | be00b11be3e7 |
hex | 5de1513f55e1 |
103222312130017 has 2 divisors, whose sum is σ = 103222312130018. Its totient is φ = 103222312130016.
The previous prime is 103222312129999. The next prime is 103222312130039. The reversal of 103222312130017 is 710031213222301.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 72839550782881 + 30382761347136 = 8534609^2 + 5512056^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-103222312130017 is a prime.
It is not a weakly prime, because it can be changed into another prime (103222312139017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51611156065008 + 51611156065009.
It is an arithmetic number, because the mean of its divisors is an integer number (51611156065009).
Almost surely, 2103222312130017 is an apocalyptic number.
It is an amenable number.
103222312130017 is a deficient number, since it is larger than the sum of its proper divisors (1).
103222312130017 is an equidigital number, since it uses as much as digits as its factorization.
103222312130017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3024, while the sum is 28.
Adding to 103222312130017 its reverse (710031213222301), we get a palindrome (813253525352318).
The spelling of 103222312130017 in words is "one hundred three trillion, two hundred twenty-two billion, three hundred twelve million, one hundred thirty thousand, seventeen".
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