Base | Representation |
---|---|
bin | 10111011110000101010001… |
… | …001111110101011000100011 |
3 | 111112110221211102002010200111 |
4 | 113132011101033311120203 |
5 | 102012143243401130313 |
6 | 1003311401530432151 |
7 | 30512365056262306 |
oct | 2736052117653043 |
9 | 445427742063614 |
10 | 103222312130083 |
11 | 2a987378219683 |
12 | b6b1213592657 |
13 | 4579a8c6a1043 |
14 | 1b6bdb51bab3d |
15 | be00b11be43d |
hex | 5de1513f5623 |
103222312130083 has 2 divisors, whose sum is σ = 103222312130084. Its totient is φ = 103222312130082.
The previous prime is 103222312130051. The next prime is 103222312130153. The reversal of 103222312130083 is 380031213222301.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 103222312130083 - 25 = 103222312130051 is a prime.
It is not a weakly prime, because it can be changed into another prime (103222312137083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51611156065041 + 51611156065042.
It is an arithmetic number, because the mean of its divisors is an integer number (51611156065042).
Almost surely, 2103222312130083 is an apocalyptic number.
103222312130083 is a deficient number, since it is larger than the sum of its proper divisors (1).
103222312130083 is an equidigital number, since it uses as much as digits as its factorization.
103222312130083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 103222312130083 its reverse (380031213222301), we get a palindrome (483253525352384).
The spelling of 103222312130083 in words is "one hundred three trillion, two hundred twenty-two billion, three hundred twelve million, one hundred thirty thousand, eighty-three".
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