Base | Representation |
---|---|
bin | 11110000010101010100… |
… | …11011110100000111011 |
3 | 10122200100102021200200220 |
4 | 33001111103132200323 |
5 | 113402443132220443 |
6 | 2110110304031123 |
7 | 134401312311522 |
oct | 17012523364073 |
9 | 3580312250626 |
10 | 1032223320123 |
11 | 368844177276 |
12 | 1480756024a3 |
13 | 76452168978 |
14 | 37d61c7d4b9 |
15 | 1bcb5666a83 |
hex | f0554de83b |
1032223320123 has 4 divisors (see below), whose sum is σ = 1376297760168. Its totient is φ = 688148880080.
The previous prime is 1032223320103. The next prime is 1032223320131. The reversal of 1032223320123 is 3210233222301.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1032223320123 - 232 = 1027928352827 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1032223320093 and 1032223320102.
It is not an unprimeable number, because it can be changed into a prime (1032223320103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 172037220018 + ... + 172037220023.
It is an arithmetic number, because the mean of its divisors is an integer number (344074440042).
Almost surely, 21032223320123 is an apocalyptic number.
1032223320123 is a deficient number, since it is larger than the sum of its proper divisors (344074440045).
1032223320123 is an equidigital number, since it uses as much as digits as its factorization.
1032223320123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 344074440044.
The product of its (nonzero) digits is 2592, while the sum is 24.
Adding to 1032223320123 its reverse (3210233222301), we get a palindrome (4242456542424).
The spelling of 1032223320123 in words is "one trillion, thirty-two billion, two hundred twenty-three million, three hundred twenty thousand, one hundred twenty-three".
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