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10322412433 is a prime number
BaseRepresentation
bin10011001110100001…
…11000001110010001
3222122101102212211121
421213100320032101
5132120014144213
64424141042241
7513541025614
oct114720701621
928571385747
1010322412433
114417807273
122000b56381
13c86734768
146dcccc17b
1540634788d
hex267438391

10322412433 has 2 divisors, whose sum is σ = 10322412434. Its totient is φ = 10322412432.

The previous prime is 10322412421. The next prime is 10322412439. The reversal of 10322412433 is 33421422301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9117767169 + 1204645264 = 95487^2 + 34708^2 .

It is a cyclic number.

It is not a de Polignac number, because 10322412433 - 225 = 10288858001 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10322412398 and 10322412407.

It is not a weakly prime, because it can be changed into another prime (10322412439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5161206216 + 5161206217.

It is an arithmetic number, because the mean of its divisors is an integer number (5161206217).

Almost surely, 210322412433 is an apocalyptic number.

It is an amenable number.

10322412433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10322412433 is an equidigital number, since it uses as much as digits as its factorization.

10322412433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 10322412433 its reverse (33421422301), we get a palindrome (43743834734).

The spelling of 10322412433 in words is "ten billion, three hundred twenty-two million, four hundred twelve thousand, four hundred thirty-three".