Base | Representation |
---|---|
bin | 10111011110001100011011… |
… | …011111001100100100010011 |
3 | 111112111200200012101121010201 |
4 | 113132030123133030210103 |
5 | 102012310020012402011 |
6 | 1003315112443040031 |
7 | 30513056431161301 |
oct | 2736143337144423 |
9 | 445450605347121 |
10 | 103230000122131 |
11 | 2a98a662960913 |
12 | b6b27ba210017 |
13 | 457a7163a086c |
14 | 1b6c504267271 |
15 | be03b10d7cc1 |
hex | 5de31b7cc913 |
103230000122131 has 2 divisors, whose sum is σ = 103230000122132. Its totient is φ = 103230000122130.
The previous prime is 103230000122089. The next prime is 103230000122143. The reversal of 103230000122131 is 131221000032301.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 103230000122131 - 217 = 103229999991059 is a prime.
It is a super-2 number, since 2×1032300001221312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 103230000122099 and 103230000122108.
It is not a weakly prime, because it can be changed into another prime (103230000122191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51615000061065 + 51615000061066.
It is an arithmetic number, because the mean of its divisors is an integer number (51615000061066).
Almost surely, 2103230000122131 is an apocalyptic number.
103230000122131 is a deficient number, since it is larger than the sum of its proper divisors (1).
103230000122131 is an equidigital number, since it uses as much as digits as its factorization.
103230000122131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 103230000122131 its reverse (131221000032301), we get a palindrome (234451000154432).
The spelling of 103230000122131 in words is "one hundred three trillion, two hundred thirty billion, one hundred twenty-two thousand, one hundred thirty-one".
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