Base | Representation |
---|---|
bin | 11110000010110101001… |
… | …10111111110000111011 |
3 | 10122200120121202111212121 |
4 | 33001122212333300323 |
5 | 113403133423320011 |
6 | 2110123203422111 |
7 | 134403442652515 |
oct | 17013246776073 |
9 | 3580517674777 |
10 | 1032312323131 |
11 | 36888a437581 |
12 | 14809b384937 |
13 | 7646772bb7b |
14 | 37d6da0abb5 |
15 | 1bcbd397e71 |
hex | f05a9bfc3b |
1032312323131 has 2 divisors, whose sum is σ = 1032312323132. Its totient is φ = 1032312323130.
The previous prime is 1032312323087. The next prime is 1032312323137. The reversal of 1032312323131 is 1313232132301.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1032312323131 - 235 = 997952584763 is a prime.
It is a super-2 number, since 2×10323123231312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1032312323096 and 1032312323105.
It is not a weakly prime, because it can be changed into another prime (1032312323137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 516156161565 + 516156161566.
It is an arithmetic number, because the mean of its divisors is an integer number (516156161566).
Almost surely, 21032312323131 is an apocalyptic number.
1032312323131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1032312323131 is an equidigital number, since it uses as much as digits as its factorization.
1032312323131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 1032312323131 its reverse (1313232132301), we get a palindrome (2345544455432).
The spelling of 1032312323131 in words is "one trillion, thirty-two billion, three hundred twelve million, three hundred twenty-three thousand, one hundred thirty-one".
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