Base | Representation |
---|---|
bin | 10111011110001110100100… |
… | …100101000001111011100001 |
3 | 111112111220121111021002210222 |
4 | 113132032210211001323201 |
5 | 102012324222313130032 |
6 | 1003320133004132425 |
7 | 30513200430004532 |
oct | 2736164445017341 |
9 | 445456544232728 |
10 | 103232300130017 |
11 | 2a990633187883 |
12 | b6b3140537115 |
13 | 457a9c1a49486 |
14 | 1b6c6818d8689 |
15 | be0497eaba12 |
hex | 5de3a4941ee1 |
103232300130017 has 2 divisors, whose sum is σ = 103232300130018. Its totient is φ = 103232300130016.
The previous prime is 103232300129951. The next prime is 103232300130041. The reversal of 103232300130017 is 710031003232301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 96366244190161 + 6866055939856 = 9816631^2 + 2620316^2 .
It is a cyclic number.
It is not a de Polignac number, because 103232300130017 - 224 = 103232283352801 is a prime.
It is not a weakly prime, because it can be changed into another prime (103232300130077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51616150065008 + 51616150065009.
It is an arithmetic number, because the mean of its divisors is an integer number (51616150065009).
Almost surely, 2103232300130017 is an apocalyptic number.
It is an amenable number.
103232300130017 is a deficient number, since it is larger than the sum of its proper divisors (1).
103232300130017 is an equidigital number, since it uses as much as digits as its factorization.
103232300130017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2268, while the sum is 26.
Adding to 103232300130017 its reverse (710031003232301), we get a palindrome (813263303362318).
The spelling of 103232300130017 in words is "one hundred three trillion, two hundred thirty-two billion, three hundred million, one hundred thirty thousand, seventeen".
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