Base | Representation |
---|---|
bin | 1001011000111100000001… |
… | …0010100100000101000011 |
3 | 1100112222010120112222120002 |
4 | 2112033000102210011003 |
5 | 2323122104310113011 |
6 | 33542443422110215 |
7 | 2113613102235443 |
oct | 226170022440503 |
9 | 40488116488502 |
10 | 10324032504131 |
11 | 3320441224385 |
12 | 11a8a4971b36b |
13 | 59b723c24178 |
14 | 279985d2c123 |
15 | 12d8423b3c3b |
hex | 963c04a4143 |
10324032504131 has 2 divisors, whose sum is σ = 10324032504132. Its totient is φ = 10324032504130.
The previous prime is 10324032504127. The next prime is 10324032504187. The reversal of 10324032504131 is 13140523042301.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10324032504131 - 22 = 10324032504127 is a prime.
It is a super-2 number, since 2×103240325041312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10324032504094 and 10324032504103.
It is not a weakly prime, because it can be changed into another prime (10324032501131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5162016252065 + 5162016252066.
It is an arithmetic number, because the mean of its divisors is an integer number (5162016252066).
Almost surely, 210324032504131 is an apocalyptic number.
10324032504131 is a deficient number, since it is larger than the sum of its proper divisors (1).
10324032504131 is an equidigital number, since it uses as much as digits as its factorization.
10324032504131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 10324032504131 its reverse (13140523042301), we get a palindrome (23464555546432).
The spelling of 10324032504131 in words is "ten trillion, three hundred twenty-four billion, thirty-two million, five hundred four thousand, one hundred thirty-one".
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