Base | Representation |
---|---|
bin | 10011001110110000… |
… | …01100101001100011 |
3 | 222122112001100202121 |
4 | 21213120030221203 |
5 | 132121012043412 |
6 | 4424250125111 |
7 | 513563236456 |
oct | 114730145143 |
9 | 28575040677 |
10 | 10324331107 |
11 | 44188a7852 |
12 | 2001720797 |
13 | c86c56b7c |
14 | 6dd26b49d |
15 | 4065c6107 |
hex | 26760ca63 |
10324331107 has 2 divisors, whose sum is σ = 10324331108. Its totient is φ = 10324331106.
The previous prime is 10324331077. The next prime is 10324331167. The reversal of 10324331107 is 70113342301.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10324331107 - 219 = 10323806819 is a prime.
It is not a weakly prime, because it can be changed into another prime (10324331167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5162165553 + 5162165554.
It is an arithmetic number, because the mean of its divisors is an integer number (5162165554).
Almost surely, 210324331107 is an apocalyptic number.
10324331107 is a deficient number, since it is larger than the sum of its proper divisors (1).
10324331107 is an equidigital number, since it uses as much as digits as its factorization.
10324331107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 10324331107 its reverse (70113342301), we get a palindrome (80437673408).
The spelling of 10324331107 in words is "ten billion, three hundred twenty-four million, three hundred thirty-one thousand, one hundred seven".
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