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103243500974153 is a prime number
BaseRepresentation
bin10111011110011001000000…
…001100110111000001001001
3111112112222112002121221102002
4113132121000030313001021
5102013020142222133103
61003325224245120345
730514045125422021
oct2736310014670111
9445488462557362
10103243500974153
112a995360824861
12b6b53476b90b5
13457ba884653b7
141b6d02532aa81
15be09014c0488
hex5de640337049

103243500974153 has 2 divisors, whose sum is σ = 103243500974154. Its totient is φ = 103243500974152.

The previous prime is 103243500974149. The next prime is 103243500974167. The reversal of 103243500974153 is 351479005342301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 89674687787584 + 13568813186569 = 9469672^2 + 3683587^2 .

It is a cyclic number.

It is not a de Polignac number, because 103243500974153 - 22 = 103243500974149 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 103243500974098 and 103243500974107.

It is not a weakly prime, because it can be changed into another prime (103243500974753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51621750487076 + 51621750487077.

It is an arithmetic number, because the mean of its divisors is an integer number (51621750487077).

Almost surely, 2103243500974153 is an apocalyptic number.

It is an amenable number.

103243500974153 is a deficient number, since it is larger than the sum of its proper divisors (1).

103243500974153 is an equidigital number, since it uses as much as digits as its factorization.

103243500974153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1360800, while the sum is 47.

The spelling of 103243500974153 in words is "one hundred three trillion, two hundred forty-three billion, five hundred million, nine hundred seventy-four thousand, one hundred fifty-three".