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10325004341273 is a prime number
BaseRepresentation
bin1001011000111111101000…
…1101110101000000011001
31100120001122022020102111022
42112033322031311000121
52323131102102410043
633543124100012225
72113646142562046
oct226177215650031
940501568212438
1010325004341273
11332089a861a76
1211a907b091075
1359b84a38062b
14279a390281cd
1512d89c880868
hex963fa375019

10325004341273 has 2 divisors, whose sum is σ = 10325004341274. Its totient is φ = 10325004341272.

The previous prime is 10325004341251. The next prime is 10325004341303. The reversal of 10325004341273 is 37214340052301.

10325004341273 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5332626325504 + 4992378015769 = 2309248^2 + 2234363^2 .

It is a cyclic number.

It is not a de Polignac number, because 10325004341273 - 218 = 10325004079129 is a prime.

It is not a weakly prime, because it can be changed into another prime (10325004341173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5162502170636 + 5162502170637.

It is an arithmetic number, because the mean of its divisors is an integer number (5162502170637).

Almost surely, 210325004341273 is an apocalyptic number.

It is an amenable number.

10325004341273 is a deficient number, since it is larger than the sum of its proper divisors (1).

10325004341273 is an equidigital number, since it uses as much as digits as its factorization.

10325004341273 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60480, while the sum is 35.

Adding to 10325004341273 its reverse (37214340052301), we get a palindrome (47539344393574).

The spelling of 10325004341273 in words is "ten trillion, three hundred twenty-five billion, four million, three hundred forty-one thousand, two hundred seventy-three".