Base | Representation |
---|---|
bin | 10111011111011000000101… |
… | …110100110100101011001011 |
3 | 111112210110101000120102101021 |
4 | 113133120011310310223023 |
5 | 102020122410203240212 |
6 | 1003420310130333311 |
7 | 30521663601641443 |
oct | 2737300564645313 |
9 | 445713330512337 |
10 | 103311241071307 |
11 | 2aa110622a2425 |
12 | b7064b172a237 |
13 | 4585292636719 |
14 | 1b7240db51123 |
15 | be25684d0307 |
hex | 5df605d34acb |
103311241071307 has 2 divisors, whose sum is σ = 103311241071308. Its totient is φ = 103311241071306.
The previous prime is 103311241071293. The next prime is 103311241071319. The reversal of 103311241071307 is 703170142113301.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 103311241071307 - 211 = 103311241069259 is a prime.
It is not a weakly prime, because it can be changed into another prime (103311241471307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51655620535653 + 51655620535654.
It is an arithmetic number, because the mean of its divisors is an integer number (51655620535654).
Almost surely, 2103311241071307 is an apocalyptic number.
103311241071307 is a deficient number, since it is larger than the sum of its proper divisors (1).
103311241071307 is an equidigital number, since it uses as much as digits as its factorization.
103311241071307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10584, while the sum is 34.
Adding to 103311241071307 its reverse (703170142113301), we get a palindrome (806481383184608).
The spelling of 103311241071307 in words is "one hundred three trillion, three hundred eleven billion, two hundred forty-one million, seventy-one thousand, three hundred seven".
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