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103311300201 = 334437100067
BaseRepresentation
bin110000000110111010…
…1010101011001101001
3100212122221102211011220
41200031311111121221
53143040143101301
6115243251412253
710315102363644
oct1401565253151
9325587384156
10103311300201
113a8a5598a3a
12180328b4089
13998584a385
145000b3ca5b
152a49cc0936
hex180dd55669

103311300201 has 4 divisors (see below), whose sum is σ = 137748400272. Its totient is φ = 68874200132.

The previous prime is 103311300199. The next prime is 103311300271. The reversal of 103311300201 is 102003113301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 103311300201 - 21 = 103311300199 is a prime.

It is a super-2 number, since 2×1033113002012 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (103311300271) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17218550031 + ... + 17218550036.

It is an arithmetic number, because the mean of its divisors is an integer number (34437100068).

Almost surely, 2103311300201 is an apocalyptic number.

It is an amenable number.

103311300201 is a deficient number, since it is larger than the sum of its proper divisors (34437100071).

103311300201 is an equidigital number, since it uses as much as digits as its factorization.

103311300201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34437100070.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 103311300201 its reverse (102003113301), we get a palindrome (205314413502).

The spelling of 103311300201 in words is "one hundred three billion, three hundred eleven million, three hundred thousand, two hundred one".

Divisors: 1 3 34437100067 103311300201