Base | Representation |
---|---|
bin | 11110000100010100101… |
… | …10001001100001001001 |
3 | 10122202122102202221020101 |
4 | 33002022112021201021 |
5 | 113411303440304001 |
6 | 2110334453325401 |
7 | 134432336263432 |
oct | 17021226114111 |
9 | 3582572687211 |
10 | 1033113213001 |
11 | 369160525a31 |
12 | 148283636861 |
13 | 76564633abc |
14 | 38008128489 |
15 | 1bd18848a01 |
hex | f08a589849 |
1033113213001 has 2 divisors, whose sum is σ = 1033113213002. Its totient is φ = 1033113213000.
The previous prime is 1033113212969. The next prime is 1033113213017. The reversal of 1033113213001 is 1003123113301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 827328499776 + 205784713225 = 909576^2 + 453635^2 .
It is a cyclic number.
It is not a de Polignac number, because 1033113213001 - 25 = 1033113212969 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1033113213001.
It is not a weakly prime, because it can be changed into another prime (1033113213061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 516556606500 + 516556606501.
It is an arithmetic number, because the mean of its divisors is an integer number (516556606501).
Almost surely, 21033113213001 is an apocalyptic number.
It is an amenable number.
1033113213001 is a deficient number, since it is larger than the sum of its proper divisors (1).
1033113213001 is an equidigital number, since it uses as much as digits as its factorization.
1033113213001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 1033113213001 its reverse (1003123113301), we get a palindrome (2036236326302).
The spelling of 1033113213001 in words is "one trillion, thirty-three billion, one hundred thirteen million, two hundred thirteen thousand, one".
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