Base | Representation |
---|---|
bin | 110000001000001001… |
… | …0100010110000100011 |
3 | 100212202210222120111011 |
4 | 1200100102202300203 |
5 | 3143131220332043 |
6 | 115251323001351 |
7 | 10316112565402 |
oct | 1402022426043 |
9 | 325683876434 |
10 | 103352511523 |
11 | 3a916886688 |
12 | 18044669257 |
13 | 9991249381 |
14 | 50063c9639 |
15 | 2a4d71159d |
hex | 18104a2c23 |
103352511523 has 2 divisors, whose sum is σ = 103352511524. Its totient is φ = 103352511522.
The previous prime is 103352511491. The next prime is 103352511553. The reversal of 103352511523 is 325115253301.
It is a strong prime.
It is an emirp because it is prime and its reverse (325115253301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 103352511523 - 25 = 103352511491 is a prime.
It is a super-2 number, since 2×1033525115232 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (103352511553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51676255761 + 51676255762.
It is an arithmetic number, because the mean of its divisors is an integer number (51676255762).
Almost surely, 2103352511523 is an apocalyptic number.
103352511523 is a deficient number, since it is larger than the sum of its proper divisors (1).
103352511523 is an equidigital number, since it uses as much as digits as its factorization.
103352511523 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 103352511523 its reverse (325115253301), we get a palindrome (428467764824).
The spelling of 103352511523 in words is "one hundred three billion, three hundred fifty-two million, five hundred eleven thousand, five hundred twenty-three".
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