Base | Representation |
---|---|
bin | 1001011001110111101010… |
… | …0101111010101000101011 |
3 | 1100121111110101012112200001 |
4 | 2112131322211322220223 |
5 | 2323402402004310243 |
6 | 33554052235323431 |
7 | 2115020622453442 |
oct | 226357245725053 |
9 | 40544411175601 |
10 | 10340043041323 |
11 | 33272078069a6 |
12 | 11abb775b0577 |
13 | 5a00a5c29608 |
14 | 27a664443d59 |
15 | 12de7cc8ba4d |
hex | 9677a97aa2b |
10340043041323 has 2 divisors, whose sum is σ = 10340043041324. Its totient is φ = 10340043041322.
The previous prime is 10340043041297. The next prime is 10340043041441. The reversal of 10340043041323 is 32314034004301.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10340043041323 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10340043041291 and 10340043041300.
It is not a weakly prime, because it can be changed into another prime (10340043041623) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5170021520661 + 5170021520662.
It is an arithmetic number, because the mean of its divisors is an integer number (5170021520662).
Almost surely, 210340043041323 is an apocalyptic number.
10340043041323 is a deficient number, since it is larger than the sum of its proper divisors (1).
10340043041323 is an equidigital number, since it uses as much as digits as its factorization.
10340043041323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 10340043041323 its reverse (32314034004301), we get a palindrome (42654077045624).
The spelling of 10340043041323 in words is "ten trillion, three hundred forty billion, forty-three million, forty-one thousand, three hundred twenty-three".
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