Base | Representation |
---|---|
bin | 11110000110000101110… |
… | …01100010001011010001 |
3 | 10122212002120002222100011 |
4 | 33003002321202023101 |
5 | 113420224333410022 |
6 | 2111012545354521 |
7 | 134465010041536 |
oct | 17030271421321 |
9 | 3585076088304 |
10 | 1034062013137 |
11 | 3695a805957a |
12 | 1484a9338a41 |
13 | 766860856ba |
14 | 38098148d8d |
15 | 1bd71cb4977 |
hex | f0c2e622d1 |
1034062013137 has 2 divisors, whose sum is σ = 1034062013138. Its totient is φ = 1034062013136.
The previous prime is 1034062013119. The next prime is 1034062013221. The reversal of 1034062013137 is 7313102604301.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1012406241856 + 21655771281 = 1006184^2 + 147159^2 .
It is a cyclic number.
It is not a de Polignac number, because 1034062013137 - 211 = 1034062011089 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1034062013099 and 1034062013108.
It is not a weakly prime, because it can be changed into another prime (1034062013737) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 517031006568 + 517031006569.
It is an arithmetic number, because the mean of its divisors is an integer number (517031006569).
Almost surely, 21034062013137 is an apocalyptic number.
It is an amenable number.
1034062013137 is a deficient number, since it is larger than the sum of its proper divisors (1).
1034062013137 is an equidigital number, since it uses as much as digits as its factorization.
1034062013137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9072, while the sum is 31.
Adding to 1034062013137 its reverse (7313102604301), we get a palindrome (8347164617438).
The spelling of 1034062013137 in words is "one trillion, thirty-four billion, sixty-two million, thirteen thousand, one hundred thirty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •