103413423433 has 4 divisors (see below), whose sum is σ = 103594533328. Its totient is φ = 103232313540.

The previous prime is 103413423343. The next prime is 103413423479. The reversal of 103413423433 is 334324314301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 334324314301 = 47 ⋅7113283283.

It is a cyclic number.

It is not a de Polignac number, because 103413423433 - 2¹⁷ = 103413292361 is a prime.

It is a super-2 number, since 2×103413423433² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 103413423395 and 103413423404.

It is not an unprimeable number, because it can be changed into a prime (103413433433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 90554091 + ... + 90555232.

It is an arithmetic number, because the mean of its divisors is an integer number (25898633332).

Almost surely, 2^103413423433 is an apocalyptic number.

It is an amenable number.

103413423433 is a deficient number, since it is larger than the sum of its proper divisors (181109895).

103413423433 is an equidigital number, since it uses as much as digits as its factorization.

103413423433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 181109894.

The product of its (nonzero) digits is 31104, while the sum is 31.

Adding to 103413423433 its reverse (334324314301), we get a palindrome (437737737734).

The spelling of 103413423433 in words is "one hundred three billion, four hundred thirteen million, four hundred twenty-three thousand, four hundred thirty-three".