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10341431232113 is a prime number
BaseRepresentation
bin1001011001111100110101…
…0101011100011001110001
31100121122001010022221102202
42112133031111130121301
52323413222343411423
633554442105152545
72115100210053062
oct226371525343161
940548033287382
1010341431232113
11332785a36a213
1211b02a448b755
135a0267701b97
1427a756960569
1512e00ea9c728
hex967cd55c671

10341431232113 has 2 divisors, whose sum is σ = 10341431232114. Its totient is φ = 10341431232112.

The previous prime is 10341431232073. The next prime is 10341431232151. The reversal of 10341431232113 is 31123213414301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6309254783329 + 4032176448784 = 2511823^2 + 2008028^2 .

It is a cyclic number.

It is not a de Polignac number, because 10341431232113 - 26 = 10341431232049 is a prime.

It is not a weakly prime, because it can be changed into another prime (10341431237113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5170715616056 + 5170715616057.

It is an arithmetic number, because the mean of its divisors is an integer number (5170715616057).

Almost surely, 210341431232113 is an apocalyptic number.

It is an amenable number.

10341431232113 is a deficient number, since it is larger than the sum of its proper divisors (1).

10341431232113 is an equidigital number, since it uses as much as digits as its factorization.

10341431232113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 10341431232113 its reverse (31123213414301), we get a palindrome (41464644646414).

The spelling of 10341431232113 in words is "ten trillion, three hundred forty-one billion, four hundred thirty-one million, two hundred thirty-two thousand, one hundred thirteen".