Base | Representation |
---|---|
bin | 11110000110010101101… |
… | …00111011100100001010 |
3 | 10122212102211101122010112 |
4 | 33003022310323210022 |
5 | 113421012411233023 |
6 | 2111034100314322 |
7 | 134501213442653 |
oct | 17031264734412 |
9 | 3585384348115 |
10 | 1034195024138 |
11 | 369666147721 |
12 | 1485259a29a2 |
13 | 766a77b6833 |
14 | 380aba9052a |
15 | 1bd7d7da478 |
hex | f0cad3b90a |
1034195024138 has 4 divisors (see below), whose sum is σ = 1551292536210. Its totient is φ = 517097512068.
The previous prime is 1034195024111. The next prime is 1034195024201. The reversal of 1034195024138 is 8314205914301.
1034195024138 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 820424727529 + 213770296609 = 905773^2 + 462353^2 .
It is a super-3 number, since 3×10341950241383 (a number of 37 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1034195024095 and 1034195024104.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 258548756033 + ... + 258548756036.
Almost surely, 21034195024138 is an apocalyptic number.
1034195024138 is a deficient number, since it is larger than the sum of its proper divisors (517097512072).
1034195024138 is an equidigital number, since it uses as much as digits as its factorization.
1034195024138 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 517097512071.
The product of its (nonzero) digits is 103680, while the sum is 41.
The spelling of 1034195024138 in words is "one trillion, thirty-four billion, one hundred ninety-five million, twenty-four thousand, one hundred thirty-eight".
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