10343031131401 has 4 divisors (see below), whose sum is σ = 10583566739152. Its totient is φ = 10102495523652.

The previous prime is 10343031131369. The next prime is 10343031131429. The reversal of 10343031131401 is 10413113034301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 10343031131401 - 2⁵ = 10343031131369 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10343031131501) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 120267803811 + ... + 120267803896.

It is an arithmetic number, because the mean of its divisors is an integer number (2645891684788).

Almost surely, 2^{10343031131401} is an apocalyptic number.

It is an amenable number.

10343031131401 is a deficient number, since it is larger than the sum of its proper divisors (240535607751).

10343031131401 is an equidigital number, since it uses as much as digits as its factorization.

10343031131401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 240535607750.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 10343031131401 its reverse (10413113034301), we get a palindrome (20756144165702).

The spelling of 10343031131401 in words is "ten trillion, three hundred forty-three billion, thirty-one million, one hundred thirty-one thousand, four hundred one".