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10343144041 = 15116845231
BaseRepresentation
bin10011010000111111…
…11101101001101001
3222200211110011020221
421220133331221221
5132140321102131
64430201250041
7514212162616
oct115037755151
928624404227
1010343144041
11442848722a
122007a93921
13c8ab12b99
1470196750d
15408090411
hex2687fda69

10343144041 has 4 divisors (see below), whose sum is σ = 10349990784. Its totient is φ = 10336297300.

The previous prime is 10343144039. The next prime is 10343144051. The reversal of 10343144041 is 14044134301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14044134301 = 41342539861.

It is a cyclic number.

It is not a de Polignac number, because 10343144041 - 21 = 10343144039 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10343143997 and 10343144015.

It is not an unprimeable number, because it can be changed into a prime (10343144011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3421105 + ... + 3424126.

It is an arithmetic number, because the mean of its divisors is an integer number (2587497696).

Almost surely, 210343144041 is an apocalyptic number.

It is an amenable number.

10343144041 is a deficient number, since it is larger than the sum of its proper divisors (6846743).

10343144041 is an equidigital number, since it uses as much as digits as its factorization.

10343144041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6846742.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 10343144041 its reverse (14044134301), we get a palindrome (24387278342).

The spelling of 10343144041 in words is "ten billion, three hundred forty-three million, one hundred forty-four thousand, forty-one".

Divisors: 1 1511 6845231 10343144041