Base | Representation |
---|---|
bin | 1001011010000011110011… |
… | …1110010000100000110001 |
3 | 1100121210212122122200111112 |
4 | 2112200330332100200301 |
5 | 2323431041333433124 |
6 | 33555352013323105 |
7 | 2115164502044402 |
oct | 226407476204061 |
9 | 40553778580445 |
10 | 10343304202289 |
11 | 3328630633453 |
12 | 11b0727796495 |
13 | 5a04a5760666 |
14 | 27a8935cd9a9 |
15 | 12e0be21b90e |
hex | 9683cf90831 |
10343304202289 has 2 divisors, whose sum is σ = 10343304202290. Its totient is φ = 10343304202288.
The previous prime is 10343304202271. The next prime is 10343304202367. The reversal of 10343304202289 is 98220240334301.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8285284425889 + 2058019776400 = 2878417^2 + 1434580^2 .
It is a cyclic number.
It is not a de Polignac number, because 10343304202289 - 224 = 10343287425073 is a prime.
It is not a weakly prime, because it can be changed into another prime (10343304202229) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5171652101144 + 5171652101145.
It is an arithmetic number, because the mean of its divisors is an integer number (5171652101145).
Almost surely, 210343304202289 is an apocalyptic number.
It is an amenable number.
10343304202289 is a deficient number, since it is larger than the sum of its proper divisors (1).
10343304202289 is an equidigital number, since it uses as much as digits as its factorization.
10343304202289 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 248832, while the sum is 41.
The spelling of 10343304202289 in words is "ten trillion, three hundred forty-three billion, three hundred four million, two hundred two thousand, two hundred eighty-nine".
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