Base | Representation |
---|---|
bin | 10011010001000001… |
… | …00110011011000001 |
3 | 222200211202122100010 |
4 | 21220200212123001 |
5 | 132140341423131 |
6 | 4430205015133 |
7 | 514213456530 |
oct | 115040463301 |
9 | 28624678303 |
10 | 10343311041 |
11 | 4428590748 |
12 | 2007b544a9 |
13 | c8ab70bbb |
14 | 7019ac317 |
15 | 4080c4b46 |
hex | 2688266c1 |
10343311041 has 16 divisors (see below), whose sum is σ = 15762790400. Its totient is φ = 5909880528.
The previous prime is 10343311001. The next prime is 10343311057. The reversal of 10343311041 is 14011334301.
It is not a de Polignac number, because 10343311041 - 26 = 10343310977 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 10343310999 and 10343311017.
It is not an unprimeable number, because it can be changed into a prime (10343311001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 285720 + ... + 319878.
It is an arithmetic number, because the mean of its divisors is an integer number (985174400).
Almost surely, 210343311041 is an apocalyptic number.
It is an amenable number.
10343311041 is a deficient number, since it is larger than the sum of its proper divisors (5419479359).
10343311041 is a wasteful number, since it uses less digits than its factorization.
10343311041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 48588.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 10343311041 its reverse (14011334301), we get a palindrome (24354645342).
The spelling of 10343311041 in words is "ten billion, three hundred forty-three million, three hundred eleven thousand, forty-one".
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