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10343311041 = 371441934159
BaseRepresentation
bin10011010001000001…
…00110011011000001
3222200211202122100010
421220200212123001
5132140341423131
64430205015133
7514213456530
oct115040463301
928624678303
1010343311041
114428590748
122007b544a9
13c8ab70bbb
147019ac317
154080c4b46
hex2688266c1

10343311041 has 16 divisors (see below), whose sum is σ = 15762790400. Its totient is φ = 5909880528.

The previous prime is 10343311001. The next prime is 10343311057. The reversal of 10343311041 is 14011334301.

It is not a de Polignac number, because 10343311041 - 26 = 10343310977 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 10343310999 and 10343311017.

It is not an unprimeable number, because it can be changed into a prime (10343311001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 285720 + ... + 319878.

It is an arithmetic number, because the mean of its divisors is an integer number (985174400).

Almost surely, 210343311041 is an apocalyptic number.

It is an amenable number.

10343311041 is a deficient number, since it is larger than the sum of its proper divisors (5419479359).

10343311041 is a wasteful number, since it uses less digits than its factorization.

10343311041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48588.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 10343311041 its reverse (14011334301), we get a palindrome (24354645342).

The spelling of 10343311041 in words is "ten billion, three hundred forty-three million, three hundred eleven thousand, forty-one".

Divisors: 1 3 7 21 14419 34159 43257 100933 102477 239113 302799 717339 492538621 1477615863 3447770347 10343311041