Base | Representation |
---|---|
bin | 11110000110100101111… |
… | …00001011010011001010 |
3 | 10122212210022112002210201 |
4 | 33003102330023103022 |
5 | 113421302233010242 |
6 | 2111055402002414 |
7 | 134504455432033 |
oct | 17032274132312 |
9 | 3585708462721 |
10 | 1034331141322 |
11 | 369725a67566 |
12 | 1485634a640a |
13 | 766c9a6474b |
14 | 380c1ba3a8a |
15 | 1bd8a7264b7 |
hex | f0d2f0b4ca |
1034331141322 has 4 divisors (see below), whose sum is σ = 1551496711986. Its totient is φ = 517165570660.
The previous prime is 1034331141293. The next prime is 1034331141341. The reversal of 1034331141322 is 2231411334301.
1034331141322 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 850048964361 + 184282176961 = 921981^2 + 429281^2 .
It is a super-2 number, since 2×10343311413222 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 258582785329 + ... + 258582785332.
Almost surely, 21034331141322 is an apocalyptic number.
1034331141322 is a deficient number, since it is larger than the sum of its proper divisors (517165570664).
1034331141322 is an equidigital number, since it uses as much as digits as its factorization.
1034331141322 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 517165570663.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 1034331141322 its reverse (2231411334301), we get a palindrome (3265742475623).
The spelling of 1034331141322 in words is "one trillion, thirty-four billion, three hundred thirty-one million, one hundred forty-one thousand, three hundred twenty-two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •