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103485433 = 376927457
BaseRepresentation
bin1100010101100…
…00111111111001
321012201121022211
412022300333321
5202443013213
614134015121
72364416542
oct612607771
9235647284
10103485433
1153462157
122a7a74a1
13185940ac
14da5b4c9
15914253d
hex62b0ff9

103485433 has 4 divisors (see below), whose sum is σ = 103516660. Its totient is φ = 103454208.

The previous prime is 103485413. The next prime is 103485461. The reversal of 103485433 is 334584301.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 40806544 + 62678889 = 6388^2 + 7917^2 .

It is a cyclic number.

It is not a de Polignac number, because 103485433 - 25 = 103485401 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 103485395 and 103485404.

It is not an unprimeable number, because it can be changed into a prime (103485413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9960 + ... + 17497.

It is an arithmetic number, because the mean of its divisors is an integer number (25879165).

Almost surely, 2103485433 is an apocalyptic number.

It is an amenable number.

103485433 is a deficient number, since it is larger than the sum of its proper divisors (31227).

103485433 is an equidigital number, since it uses as much as digits as its factorization.

103485433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31226.

The product of its (nonzero) digits is 17280, while the sum is 31.

The square root of 103485433 is about 10172.7790205037. The cubic root of 103485433 is about 469.4900656194.

The spelling of 103485433 in words is "one hundred three million, four hundred eighty-five thousand, four hundred thirty-three".

Divisors: 1 3769 27457 103485433