103510115131 has 2 divisors, whose sum is σ = 103510115132. Its totient is φ = 103510115130.

The previous prime is 103510115099. The next prime is 103510115141. The reversal of 103510115131 is 131511015301.

It is a strong prime.

It is an emirp because it is prime and its reverse (131511015301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 103510115131 - 2⁵ = 103510115099 is a prime.

It is a super-3 number, since 3×103510115131³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (103510115141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51755057565 + 51755057566.

It is an arithmetic number, because the mean of its divisors is an integer number (51755057566).

Almost surely, 2^103510115131 is an apocalyptic number.

103510115131 is a deficient number, since it is larger than the sum of its proper divisors (1).

103510115131 is an equidigital number, since it uses as much as digits as its factorization.

103510115131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 225, while the sum is 22.

The spelling of 103510115131 in words is "one hundred three billion, five hundred ten million, one hundred fifteen thousand, one hundred thirty-one".