103544135131 has 4 divisors (see below), whose sum is σ = 105497798112. Its totient is φ = 101590472152.

The previous prime is 103544135117. The next prime is 103544135141. The reversal of 103544135131 is 131531445301.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 131531445301 = 31307 ⋅4201343.

It is a cyclic number.

It is not a de Polignac number, because 103544135131 - 2²¹ = 103542037979 is a prime.

It is a super-3 number, since 3×103544135131³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 103544135093 and 103544135102.

It is not an unprimeable number, because it can be changed into a prime (103544135141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 976831411 + ... + 976831516.

It is an arithmetic number, because the mean of its divisors is an integer number (26374449528).

Almost surely, 2^103544135131 is an apocalyptic number.

103544135131 is a deficient number, since it is larger than the sum of its proper divisors (1953662981).

103544135131 is an equidigital number, since it uses as much as digits as its factorization.

103544135131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1953662980.

The product of its (nonzero) digits is 10800, while the sum is 31.

The spelling of 103544135131 in words is "one hundred three billion, five hundred forty-four million, one hundred thirty-five thousand, one hundred thirty-one".