Base | Representation |
---|---|
bin | 11110001000110000001… |
… | …01110101001111101010 |
3 | 10122222210011120021202212 |
4 | 33010120011311033222 |
5 | 113431141233102310 |
6 | 2111410444125122 |
7 | 134545303553564 |
oct | 17043005651752 |
9 | 3588704507685 |
10 | 1035491300330 |
11 | 36a170931163 |
12 | 148827b367a2 |
13 | 76853219876 |
14 | 38191cc2334 |
15 | 1be074e2205 |
hex | f1181753ea |
1035491300330 has 16 divisors (see below), whose sum is σ = 1864115479080. Its totient is φ = 414145156032.
The previous prime is 1035491300251. The next prime is 1035491300339. The reversal of 1035491300330 is 330031945301.
1035491300330 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 4 ways, for example, as 812105566561 + 223385733769 = 901169^2 + 472637^2 .
It is a super-3 number, since 3×10354913003303 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (1035491300339) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 6335789 + ... + 6497168.
Almost surely, 21035491300330 is an apocalyptic number.
1035491300330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1035491300330 is a deficient number, since it is larger than the sum of its proper divisors (828624178750).
1035491300330 is a wasteful number, since it uses less digits than its factorization.
1035491300330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12841033.
The product of its (nonzero) digits is 14580, while the sum is 32.
The spelling of 1035491300330 in words is "one trillion, thirty-five billion, four hundred ninety-one million, three hundred thousand, three hundred thirty".
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