Base | Representation |
---|---|
bin | 1001011010101111110011… |
… | …1001101001100010010011 |
3 | 1100122221100201011101210022 |
4 | 2112223330321221202103 |
5 | 2324124233210413011 |
6 | 34005023533454055 |
7 | 2116063245013025 |
oct | 226537471514223 |
9 | 40587321141708 |
10 | 10355114154131 |
11 | 3332640a8a02a |
12 | 11b2a8294132b |
13 | 5a1638413846 |
14 | 27b293c9a015 |
15 | 12e560e4b8db |
hex | 96afce69893 |
10355114154131 has 2 divisors, whose sum is σ = 10355114154132. Its totient is φ = 10355114154130.
The previous prime is 10355114154103. The next prime is 10355114154139. The reversal of 10355114154131 is 13145141155301.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10355114154131 - 222 = 10355109959827 is a prime.
It is a super-3 number, since 3×103551141541313 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 10355114154091 and 10355114154100.
It is not a weakly prime, because it can be changed into another prime (10355114154139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5177557077065 + 5177557077066.
It is an arithmetic number, because the mean of its divisors is an integer number (5177557077066).
Almost surely, 210355114154131 is an apocalyptic number.
10355114154131 is a deficient number, since it is larger than the sum of its proper divisors (1).
10355114154131 is an equidigital number, since it uses as much as digits as its factorization.
10355114154131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18000, while the sum is 35.
The spelling of 10355114154131 in words is "ten trillion, three hundred fifty-five billion, one hundred fourteen million, one hundred fifty-four thousand, one hundred thirty-one".
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