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103601145481 is a prime number
BaseRepresentation
bin110000001111100011…
…1000000011010001001
3100220102010211111011021
41200133013000122021
53144133343123411
6115332124032441
710325222130631
oct1403707003211
9326363744137
10103601145481
113aa34166a99
12180b3992721
139a00901062
14502b42b6c1
152a65475a71
hex181f1c0689

103601145481 has 2 divisors, whose sum is σ = 103601145482. Its totient is φ = 103601145480.

The previous prime is 103601145457. The next prime is 103601145499. The reversal of 103601145481 is 184541106301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 103584204025 + 16941456 = 321845^2 + 4116^2 .

It is an emirp because it is prime and its reverse (184541106301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 103601145481 - 231 = 101453661833 is a prime.

It is a super-3 number, since 3×1036011454813 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (103601140481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51800572740 + 51800572741.

It is an arithmetic number, because the mean of its divisors is an integer number (51800572741).

Almost surely, 2103601145481 is an apocalyptic number.

It is an amenable number.

103601145481 is a deficient number, since it is larger than the sum of its proper divisors (1).

103601145481 is an equidigital number, since it uses as much as digits as its factorization.

103601145481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11520, while the sum is 34.

The spelling of 103601145481 in words is "one hundred three billion, six hundred one million, one hundred forty-five thousand, four hundred eighty-one".