104000404102131 has 4 divisors (see below), whose sum is σ = 138667205469512. Its totient is φ = 69333602734752.

The previous prime is 104000404102081. The next prime is 104000404102169. The reversal of 104000404102131 is 131201404000401.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 104000404102131 - 2¹³ = 104000404093939 is a prime.

It is a super-2 number, since 2×104000404102131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 104000404102098 and 104000404102107.

It is not an unprimeable number, because it can be changed into a prime (104000404102831) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17333400683686 + ... + 17333400683691.

It is an arithmetic number, because the mean of its divisors is an integer number (34666801367378).

Almost surely, 2^{104000404102131} is an apocalyptic number.

104000404102131 is a deficient number, since it is larger than the sum of its proper divisors (34666801367381).

104000404102131 is an equidigital number, since it uses as much as digits as its factorization.

104000404102131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34666801367380.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 104000404102131 its reverse (131201404000401), we get a palindrome (235201808102532).

The spelling of 104000404102131 in words is "one hundred four trillion, four hundred four million, one hundred two thousand, one hundred thirty-one".