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104000413305 = 357738969419
BaseRepresentation
bin110000011011011101…
…0000101111001111001
3100221102222010101122110
41200312322011321321
53200443101211210
6115435505442533
710341140633025
oct1406672057171
9327388111573
10104000413305
11401195818a8
12181a5640449
139a655472c9
145068481385
152a8a542420
hex1836e85e79

104000413305 has 16 divisors (see below), whose sum is σ = 166615945920. Its totient is φ = 55395125568.

The previous prime is 104000413303. The next prime is 104000413331. The reversal of 104000413305 is 503314000401.

It is not a de Polignac number, because 104000413305 - 21 = 104000413303 is a prime.

It is a super-2 number, since 2×1040004133052 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (104000413301) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4473115 + ... + 4496304.

It is an arithmetic number, because the mean of its divisors is an integer number (10413496620).

Almost surely, 2104000413305 is an apocalyptic number.

104000413305 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

104000413305 is a deficient number, since it is larger than the sum of its proper divisors (62615532615).

104000413305 is an equidigital number, since it uses as much as digits as its factorization.

104000413305 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8970200.

The product of its (nonzero) digits is 720, while the sum is 21.

Adding to 104000413305 its reverse (503314000401), we get a palindrome (607314413706).

The spelling of 104000413305 in words is "one hundred four billion, four hundred thirteen thousand, three hundred five".

Divisors: 1 3 5 15 773 2319 3865 11595 8969419 26908257 44847095 134541285 6933360887 20800082661 34666804435 104000413305