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10401213313 is a prime number
BaseRepresentation
bin10011010111111010…
…11110101110000001
3222211212201101022201
421223331132232001
5132300202311223
64440034033201
7515515566031
oct115375365601
928755641281
1010401213313
114458239567
122023418801
13c99b650ba
147095618c1
1540d210ead
hex26bf5eb81

10401213313 has 2 divisors, whose sum is σ = 10401213314. Its totient is φ = 10401213312.

The previous prime is 10401213299. The next prime is 10401213353. The reversal of 10401213313 is 31331210401.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9237516544 + 1163696769 = 96112^2 + 34113^2 .

It is an emirp because it is prime and its reverse (31331210401) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10401213313 - 229 = 9864342401 is a prime.

It is not a weakly prime, because it can be changed into another prime (10401213353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5200606656 + 5200606657.

It is an arithmetic number, because the mean of its divisors is an integer number (5200606657).

Almost surely, 210401213313 is an apocalyptic number.

It is an amenable number.

10401213313 is a deficient number, since it is larger than the sum of its proper divisors (1).

10401213313 is an equidigital number, since it uses as much as digits as its factorization.

10401213313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 10401213313 its reverse (31331210401), we get a palindrome (41732423714).

The spelling of 10401213313 in words is "ten billion, four hundred one million, two hundred thirteen thousand, three hundred thirteen".