10401311211481 has 2 divisors, whose sum is σ = 10401311211482. Its totient is φ = 10401311211480.

The previous prime is 10401311211461. The next prime is 10401311211559. The reversal of 10401311211481 is 18411211310401.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5499001550025 + 4902309661456 = 2344995^2 + 2214116^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10401311211481 is a prime.

It is a super-2 number, since 2×10401311211481² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10401311211461) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5200655605740 + 5200655605741.

It is an arithmetic number, because the mean of its divisors is an integer number (5200655605741).

Almost surely, 2^{10401311211481} is an apocalyptic number.

It is an amenable number.

10401311211481 is a deficient number, since it is larger than the sum of its proper divisors (1).

10401311211481 is an equidigital number, since it uses as much as digits as its factorization.

10401311211481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 28.

Adding to 10401311211481 its reverse (18411211310401), we get a palindrome (28812522521882).

The spelling of 10401311211481 in words is "ten trillion, four hundred one billion, three hundred eleven million, two hundred eleven thousand, four hundred eighty-one".