104014341200131 has 2 divisors, whose sum is σ = 104014341200132. Its totient is φ = 104014341200130.

The previous prime is 104014341200117. The next prime is 104014341200149. The reversal of 104014341200131 is 131002143410401.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 104014341200131 - 2²¹ = 104014339102979 is a prime.

It is a super-2 number, since 2×104014341200131² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 104014341200096 and 104014341200105.

It is not a weakly prime, because it can be changed into another prime (104014341260131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52007170600065 + 52007170600066.

It is an arithmetic number, because the mean of its divisors is an integer number (52007170600066).

Almost surely, 2^{104014341200131} is an apocalyptic number.

104014341200131 is a deficient number, since it is larger than the sum of its proper divisors (1).

104014341200131 is an equidigital number, since it uses as much as digits as its factorization.

104014341200131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 104014341200131 its reverse (131002143410401), we get a palindrome (235016484610532).

The spelling of 104014341200131 in words is "one hundred four trillion, fourteen billion, three hundred forty-one million, two hundred thousand, one hundred thirty-one".