Base | Representation |
---|---|
bin | 1001011101011100011001… |
… | …1011111010101010000011 |
3 | 1100211100221120212210001111 |
4 | 2113113012123322222003 |
5 | 2330404124411434111 |
6 | 34042205145144151 |
7 | 2122323334660312 |
oct | 227270633725203 |
9 | 40740846783044 |
10 | 10401445030531 |
11 | 3350256611225 |
12 | 11bba52a8b057 |
13 | 5a5b0cc807c9 |
14 | 27d60b1a6279 |
15 | 130873628a21 |
hex | 975c66faa83 |
10401445030531 has 2 divisors, whose sum is σ = 10401445030532. Its totient is φ = 10401445030530.
The previous prime is 10401445030507. The next prime is 10401445030547. The reversal of 10401445030531 is 13503054410401.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10401445030531 - 29 = 10401445030019 is a prime.
It is a super-2 number, since 2×104014450305312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10401445030493 and 10401445030502.
It is not a weakly prime, because it can be changed into another prime (10401445030591) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5200722515265 + 5200722515266.
It is an arithmetic number, because the mean of its divisors is an integer number (5200722515266).
Almost surely, 210401445030531 is an apocalyptic number.
10401445030531 is a deficient number, since it is larger than the sum of its proper divisors (1).
10401445030531 is an equidigital number, since it uses as much as digits as its factorization.
10401445030531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 10401445030531 its reverse (13503054410401), we get a palindrome (23904499440932).
The spelling of 10401445030531 in words is "ten trillion, four hundred one billion, four hundred forty-five million, thirty thousand, five hundred thirty-one".
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