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10401445104403 = 73931406931571
BaseRepresentation
bin1001011101011100011001…
…1100001100101100010011
31100211100221121000112101111
42113113012130030230103
52330404124421320103
634042205150514151
72122323335415553
oct227270634145423
940740847015344
1010401445104403
113350256661781
1211bba52b05957
135a5b0cca8312
1427d60b1c5163
1513087364086d
hex975c670cb13

10401445104403 has 4 divisors (see below), whose sum is σ = 10402852043368. Its totient is φ = 10400038165440.

The previous prime is 10401445104383. The next prime is 10401445104443. The reversal of 10401445104403 is 30440154410401.

10401445104403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10401445104403 - 217 = 10401444973331 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10401445104443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 703458393 + ... + 703473178.

It is an arithmetic number, because the mean of its divisors is an integer number (2600713010842).

Almost surely, 210401445104403 is an apocalyptic number.

10401445104403 is a deficient number, since it is larger than the sum of its proper divisors (1406938965).

10401445104403 is an equidigital number, since it uses as much as digits as its factorization.

10401445104403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1406938964.

The product of its (nonzero) digits is 15360, while the sum is 31.

Adding to 10401445104403 its reverse (30440154410401), we get a palindrome (40841599514804).

The spelling of 10401445104403 in words is "ten trillion, four hundred one billion, four hundred forty-five million, one hundred four thousand, four hundred three".

Divisors: 1 7393 1406931571 10401445104403