10404113004121 has 4 divisors (see below), whose sum is σ = 10431564490000. Its totient is φ = 10376661518244.

The previous prime is 10404113004097. The next prime is 10404113004127. The reversal of 10404113004121 is 12140031140401.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10404113004121 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10404113004092 and 10404113004101.

It is not an unprimeable number, because it can be changed into a prime (10404113004127) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13725742371 + ... + 13725743128.

It is an arithmetic number, because the mean of its divisors is an integer number (2607891122500).

Almost surely, 2^{10404113004121} is an apocalyptic number.

It is an amenable number.

10404113004121 is a deficient number, since it is larger than the sum of its proper divisors (27451485879).

10404113004121 is an equidigital number, since it uses as much as digits as its factorization.

10404113004121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27451485878.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 10404113004121 its reverse (12140031140401), we get a palindrome (22544144144522).

The spelling of 10404113004121 in words is "ten trillion, four hundred four billion, one hundred thirteen million, four thousand, one hundred twenty-one".