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10404212232433 is a prime number
BaseRepresentation
bin1001011101100110101101…
…0111111101000011110001
31100211122002102212012102211
42113121223113331003301
52330430311312414213
634043343520012121
72122452035544325
oct227315327750361
940748072765384
1010404212232433
113351446627a48
1212004a5761041
135a6161366296
1427d7d08cd985
1513098653553d
hex9766b5fd0f1

10404212232433 has 2 divisors, whose sum is σ = 10404212232434. Its totient is φ = 10404212232432.

The previous prime is 10404212232377. The next prime is 10404212232457. The reversal of 10404212232433 is 33423221240401.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9460250365504 + 943961866929 = 3075752^2 + 971577^2 .

It is a cyclic number.

It is not a de Polignac number, because 10404212232433 - 221 = 10404210135281 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10404212232395 and 10404212232404.

It is not a weakly prime, because it can be changed into another prime (10404212232493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5202106116216 + 5202106116217.

It is an arithmetic number, because the mean of its divisors is an integer number (5202106116217).

Almost surely, 210404212232433 is an apocalyptic number.

It is an amenable number.

10404212232433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10404212232433 is an equidigital number, since it uses as much as digits as its factorization.

10404212232433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 10404212232433 its reverse (33423221240401), we get a palindrome (43827433472834).

The spelling of 10404212232433 in words is "ten trillion, four hundred four billion, two hundred twelve million, two hundred thirty-two thousand, four hundred thirty-three".