1040435131531 has 2 divisors, whose sum is σ = 1040435131532. Its totient is φ = 1040435131530.

The previous prime is 1040435131511. The next prime is 1040435131607. The reversal of 1040435131531 is 1351315340401.

1040435131531 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1040435131531 - 2⁵ = 1040435131499 is a prime.

It is a super-2 number, since 2×1040435131531² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1040435131493 and 1040435131502.

It is not a weakly prime, because it can be changed into another prime (1040435131511) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520217565765 + 520217565766.

It is an arithmetic number, because the mean of its divisors is an integer number (520217565766).

Almost surely, 2^{1040435131531} is an apocalyptic number.

1040435131531 is a deficient number, since it is larger than the sum of its proper divisors (1).

1040435131531 is an equidigital number, since it uses as much as digits as its factorization.

1040435131531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10800, while the sum is 31.

The spelling of 1040435131531 in words is "one trillion, forty billion, four hundred thirty-five million, one hundred thirty-one thousand, five hundred thirty-one".