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104110333113 = 392948717669
BaseRepresentation
bin110000011110101110…
…1011001110010111001
3100221201121221220021110
41200331131121302321
53201204221124423
6115454433430533
710343644141653
oct1407535316271
9327647856243
10104110333113
1140175629216
121821640b449
139a82252007
145078cd56d3
152a95006193
hex183d759cb9

104110333113 has 16 divisors (see below), whose sum is σ = 139009852800. Its totient is φ = 69308904960.

The previous prime is 104110333087. The next prime is 104110333121. The reversal of 104110333113 is 311333011401.

It is not a de Polignac number, because 104110333113 - 25 = 104110333081 is a prime.

It is a super-2 number, since 2×1041103331132 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 104110333113.

It is not an unprimeable number, because it can be changed into a prime (104110333013) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 13571643 + ... + 13579311.

It is an arithmetic number, because the mean of its divisors is an integer number (8688115800).

Almost surely, 2104110333113 is an apocalyptic number.

It is an amenable number.

104110333113 is a deficient number, since it is larger than the sum of its proper divisors (34899519687).

104110333113 is an equidigital number, since it uses as much as digits as its factorization.

104110333113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13472.

The product of its (nonzero) digits is 324, while the sum is 21.

Adding to 104110333113 its reverse (311333011401), we get a palindrome (415443344514).

The spelling of 104110333113 in words is "one hundred four billion, one hundred ten million, three hundred thirty-three thousand, one hundred thirteen".

Divisors: 1 3 929 2787 4871 7669 14613 23007 4525159 7124501 13575477 21373503 37355699 112067097 34703444371 104110333113