Base | Representation |
---|---|
bin | 1001011110000000011000… |
… | …0011000110000011000011 |
3 | 1100212021212121112211002220 |
4 | 2113200012003012003003 |
5 | 2331033414130400003 |
6 | 34050443323542123 |
7 | 2123114550365331 |
oct | 227400603060303 |
9 | 40767777484086 |
10 | 10411102200003 |
11 | 335436185861a |
12 | 12018a908a943 |
13 | 5a69bb92517b |
14 | 27dc859a6b51 |
15 | 130c3b367353 |
hex | 978060c60c3 |
10411102200003 has 8 divisors (see below), whose sum is σ = 13881484505616. Its totient is φ = 6940727347200.
The previous prime is 10411102200001. The next prime is 10411102200029. The reversal of 10411102200003 is 30000220111401.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 10411102200003 - 21 = 10411102200001 is a prime.
It is a super-2 number, since 2×104111022000032 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (10411102200001) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4539283 + ... + 6436403.
It is an arithmetic number, because the mean of its divisors is an integer number (1735185563202).
Almost surely, 210411102200003 is an apocalyptic number.
10411102200003 is a deficient number, since it is larger than the sum of its proper divisors (3470382305613).
10411102200003 is a wasteful number, since it uses less digits than its factorization.
10411102200003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3726405.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 10411102200003 its reverse (30000220111401), we get a palindrome (40411322311404).
The spelling of 10411102200003 in words is "ten trillion, four hundred eleven billion, one hundred two million, two hundred thousand, three".
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