Base | Representation |
---|---|
bin | 10011011001001000… |
… | …00010001100111001 |
3 | 222212120201212020221 |
4 | 21230210002030321 |
5 | 132310244220441 |
6 | 4441034420041 |
7 | 516000521656 |
oct | 115444021471 |
9 | 28776655227 |
10 | 10411320121 |
11 | 4462a119a4 |
12 | 2026891621 |
13 | c9bc93467 |
14 | 70aa32c2d |
15 | 40e05a8d1 |
hex | 26c902339 |
10411320121 has 2 divisors, whose sum is σ = 10411320122. Its totient is φ = 10411320120.
The previous prime is 10411320107. The next prime is 10411320133. The reversal of 10411320121 is 12102311401.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7732740096 + 2678580025 = 87936^2 + 51755^2 .
It is a cyclic number.
It is not a de Polignac number, because 10411320121 - 217 = 10411189049 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10411320095 and 10411320104.
It is not a weakly prime, because it can be changed into another prime (10411320721) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5205660060 + 5205660061.
It is an arithmetic number, because the mean of its divisors is an integer number (5205660061).
Almost surely, 210411320121 is an apocalyptic number.
It is an amenable number.
10411320121 is a deficient number, since it is larger than the sum of its proper divisors (1).
10411320121 is an equidigital number, since it uses as much as digits as its factorization.
10411320121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 10411320121 its reverse (12102311401), we get a palindrome (22513631522).
The spelling of 10411320121 in words is "ten billion, four hundred eleven million, three hundred twenty thousand, one hundred twenty-one".
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