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1041143540153 is a prime number
BaseRepresentation
bin11110010011010001111…
…11011010100110111001
310200112101002020211011112
433021220333122212321
5114024230221241103
62114143355210105
7135135336034103
oct17115077324671
93615332224145
101041143540153
11371601427642
12149944a46935
1377244234a82
143856a848573
151c138834cd8
hexf268fda9b9

1041143540153 has 2 divisors, whose sum is σ = 1041143540154. Its totient is φ = 1041143540152.

The previous prime is 1041143540149. The next prime is 1041143540201. The reversal of 1041143540153 is 3510453411401.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 801046480144 + 240097060009 = 895012^2 + 489997^2 .

It is a cyclic number.

It is not a de Polignac number, because 1041143540153 - 22 = 1041143540149 is a prime.

It is not a weakly prime, because it can be changed into another prime (1041143540053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 520571770076 + 520571770077.

It is an arithmetic number, because the mean of its divisors is an integer number (520571770077).

Almost surely, 21041143540153 is an apocalyptic number.

It is an amenable number.

1041143540153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1041143540153 is an equidigital number, since it uses as much as digits as its factorization.

1041143540153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14400, while the sum is 32.

Adding to 1041143540153 its reverse (3510453411401), we get a palindrome (4551596951554).

The spelling of 1041143540153 in words is "one trillion, forty-one billion, one hundred forty-three million, five hundred forty thousand, one hundred fifty-three".