Base | Representation |
---|---|
bin | 1001011110000011100111… |
… | …1011001101011101010001 |
3 | 1100212101010021021002200221 |
4 | 2113200321323031131101 |
5 | 2331042204433022213 |
6 | 34051105534313041 |
7 | 2123145246256321 |
oct | 227407173153521 |
9 | 40771107232627 |
10 | 10411972548433 |
11 | 3354769078245 |
12 | 1201ab0658781 |
13 | 5a6aca039341 |
14 | 27dd29405281 |
15 | 130c8c98838d |
hex | 97839ecd751 |
10411972548433 has 2 divisors, whose sum is σ = 10411972548434. Its totient is φ = 10411972548432.
The previous prime is 10411972548403. The next prime is 10411972548529. The reversal of 10411972548433 is 33484527911401.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10378242654784 + 33729893649 = 3221528^2 + 183657^2 .
It is a cyclic number.
It is not a de Polignac number, because 10411972548433 - 213 = 10411972540241 is a prime.
It is not a weakly prime, because it can be changed into another prime (10411972548403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5205986274216 + 5205986274217.
It is an arithmetic number, because the mean of its divisors is an integer number (5205986274217).
Almost surely, 210411972548433 is an apocalyptic number.
It is an amenable number.
10411972548433 is a deficient number, since it is larger than the sum of its proper divisors (1).
10411972548433 is an equidigital number, since it uses as much as digits as its factorization.
10411972548433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2903040, while the sum is 52.
The spelling of 10411972548433 in words is "ten trillion, four hundred eleven billion, nine hundred seventy-two million, five hundred forty-eight thousand, four hundred thirty-three".
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